Engineering Mechanics Notes – Complete Study Material for First Year

Engineering Mechanics is a fundamental subject for all engineering branches. These comprehensive notes cover Statics and Dynamics with solved examples, formulas, and important concepts for university exams.

Course Overview

TopicWeightage
Statics – Force Systems20%
Equilibrium15%
Friction15%
Centroid & Moment of Inertia20%
Kinematics15%
Kinetics15%

Unit 1: Statics – Force Systems

1.1 Basic Concepts

  • Force: An action that changes or tends to change the state of rest or motion of a body
  • Types: Contact forces, Body forces, Point forces, Distributed forces
  • Characteristics: Magnitude, Direction, Point of application, Line of action

1.2 Resolution of Forces

Rectangular Components:

  • Fx = F cos θ (Horizontal component)
  • Fy = F sin θ (Vertical component)
  • F = √(Fx² + Fy²)
  • θ = tan⁻¹(Fy/Fx)

1.3 Resultant of Concurrent Forces

Parallelogram Law:

R = √(P² + Q² + 2PQ cos θ)

tan α = Q sin θ / (P + Q cos θ)

1.4 Moment of a Force

Moment = Force × Perpendicular distance

M = F × d (Unit: N-m)

Varignons Theorem: Moment of resultant = Sum of moments of components

1.5 Couple

  • Two equal, opposite, parallel forces
  • Moment of couple = F × d (arm of couple)
  • A couple can only be balanced by another couple

Unit 2: Equilibrium

2.1 Conditions of Equilibrium

For Coplanar Forces:

  • ΣFx = 0 (Sum of horizontal forces = 0)
  • ΣFy = 0 (Sum of vertical forces = 0)
  • ΣM = 0 (Sum of moments about any point = 0)

2.2 Types of Supports

SupportReactionsUnknowns
RollerNormal only1
Hinged/PinnedHorizontal + Vertical2
FixedH + V + Moment3

2.3 Free Body Diagram (FBD)

Steps to draw FBD:

  1. Isolate the body from surroundings
  2. Show all external forces
  3. Replace supports with their reactions
  4. Include weight acting at center of gravity

Unit 3: Friction

3.1 Laws of Friction

  1. Friction acts opposite to direction of motion/tendency
  2. Friction is proportional to normal reaction: f = μN
  3. Friction is independent of area of contact
  4. Friction depends on nature of surfaces

3.2 Types of Friction

  • Static friction: fs ≤ μsN (limiting friction = μsN)
  • Kinetic friction: fk = μkN (μk < μs)
  • Angle of friction: tan φ = μ
  • Angle of repose: α = φ (for inclined plane)

3.3 Applications

  • Ladder problems
  • Wedge friction
  • Belt and pulley friction: T1/T2 = e^(μθ)
  • Screw jack: P = W tan(α ± φ)

Unit 4: Centroid and Moment of Inertia

4.1 Centroid

For composite areas:

x̄ = ΣAixi / ΣAi

ȳ = ΣAiyi / ΣAi

4.2 Moment of Inertia (Second Moment of Area)

ShapeIxx (about centroid)Iyy (about centroid)
Rectangle (b×d)bd³/12db³/12
Triangle (base b, height h)bh³/36hb³/36
Circle (radius r)πr⁴/4πr⁴/4
Semicircle0.11r⁴πr⁴/8

4.3 Parallel Axis Theorem

I = Ic + Ad²

Where: Ic = MI about centroidal axis, A = area, d = distance between axes

Unit 5: Kinematics

5.1 Rectilinear Motion

  • v = u + at
  • s = ut + ½at²
  • v² = u² + 2as
  • s = ½(u + v)t

5.2 Projectile Motion

  • Range: R = u²sin2θ/g
  • Max Height: H = u²sin²θ/2g
  • Time of Flight: T = 2u sinθ/g
  • Trajectory: y = x tanθ – gx²/2u²cos²θ

5.3 Circular Motion

  • Angular velocity: ω = dθ/dt (rad/s)
  • Angular acceleration: α = dω/dt (rad/s²)
  • v = rω, a_t = rα, a_n = v²/r = rω²

Unit 6: Kinetics

6.1 Newtons Laws of Motion

  • Second Law: F = ma
  • DAlemberts Principle: F – ma = 0 (Inertia force = -ma)

6.2 Work, Energy, Power

  • Work: W = F.s.cosθ (Joules)
  • Kinetic Energy: KE = ½mv²
  • Potential Energy: PE = mgh
  • Power: P = W/t = F.v (Watts)
  • Work-Energy Theorem: W = ΔKE

6.3 Impulse and Momentum

  • Momentum: p = mv
  • Impulse: J = FΔt = Δp
  • Conservation: m1u1 + m2u2 = m1v1 + m2v2
  • Coefficient of restitution: e = (v2-v1)/(u1-u2)

Important Solved Problems

Practice these types for exam:

  1. Finding resultant of force system
  2. Equilibrium of rigid bodies
  3. Ladder and friction problems
  4. Centroid of composite sections
  5. Moment of inertia calculations
  6. Projectile motion problems
  7. Collision and momentum problems

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Engineering Mechanics: Key Topics for First-Year Exam

Statics: Forces and Equilibrium

  • Types of Forces: Concurrent (acting at the same point), coplanar (in the same plane), collinear (along the same line), parallel forces
  • Resolution of Forces: Any force can be resolved into horizontal (Fx = F cos θ) and vertical (Fy = F sin θ) components
  • Resultant of Forces: For concurrent forces — R = √(ΣFx)2 + (ΣFy)2; direction: tan α = ΣFy/ΣFx
  • Lami Theorem: For three concurrent coplanar forces in equilibrium: F1/sin α = F2/sin β = F3/sin γ, where α, β, γ are the angles opposite to respective forces
  • Conditions of Equilibrium: ΣFx = 0, ΣFy = 0, ΣM = 0 (sum of moments = 0)

Moment and Couple

  • Moment of a Force: M = F × d (Force × perpendicular distance from the pivot). Clockwise = negative; anticlockwise = positive (by convention)
  • Varignon Theorem: The moment of a resultant force about any point equals the sum of moments of its components about the same point
  • Couple: Two equal, opposite, parallel forces separated by a distance d. Moment of couple = F × d. A couple only produces rotation, not translation.

Centroid and Centre of Gravity

  • Centroid: Geometric centre of a plane figure. For simple shapes: rectangle (centre), triangle (1/3 from base), semicircle (4r/3π from diameter)
  • Composite Areas: x̄ = (A1x1 + A2x2 + …)/( A1 + A2 + …); ȳ similarly
  • For areas with holes: subtract the hole area and its moment

Friction

  • Laws of Dry Friction (Coulomb): F = μN (friction force = coefficient of friction × normal reaction); friction is independent of contact area; static friction is greater than kinetic friction
  • Angle of Friction: φ = tan-1(μs)
  • Angle of Repose: Maximum angle at which a body rests on an inclined plane without sliding = angle of friction
  • Common applications: wedge, screw jack, belt drive, ladder

Kinematics (Dynamics)

  • Equations of motion (uniform acceleration): v = u + at; s = ut + 0.5at2; v2 = u2 + 2as
  • Projectile motion: Horizontal: x = v0cosθ × t; Vertical: y = v0sinθ × t – 0.5gt2. Range = v02 sin 2θ / g; Max height = v02 sin2θ / 2g
  • Curvilinear motion: Normal acceleration an = v2/r; Tangential acceleration at = dv/dt

Common University Exam Questions in Engineering Mechanics

  • Find the resultant of a system of concurrent coplanar forces (magnitude and direction)
  • A body rests on an inclined plane — find the minimum force required to prevent sliding (friction problems)
  • Find the centroid of a composite area (T-section, I-section, L-section)
  • Determine forces in the members of a truss using the method of joints or method of sections
  • A particle is projected at 30° with initial velocity 40 m/s — find range, maximum height, time of flight

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